JAXB Object to XML conversion using java (Marshalling)

convert person object into an XML. 

public class ObjectToXML {

public static void main(String args[]) {

Person person = new Person();

person.setFirtName("Aneesh");

person.setLastName("T.G");

person.setAge(25);

try {

JAXBContext jaxbContext = JAXBContext.newInstance(Person.class);

Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

// print output to console

jaxbMarshaller.marshal(person, System.out);

} catch (JAXBException e) {

e.printStackTrace();

}

}

}

use the annotation @XmlRootElement to the class you want to convert into XML.

use the annotation @XmlType propOrder for ordering the tags in the XML.

@XmlRootElement

@XmlType(propOrder={"firtName","lastName","age"})

public class Person {

private String firtName;

private String lastName;

private int age;

public String getFirtName() {

return firtName;

}

public void setFirtName(String firtName) {

this.firtName = firtName;

}

public String getLastName() {

return lastName;

}

public void setLastName(String lastName) {

this.lastName = lastName;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

}

Output

---------

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>

<person>

    <firtName>Aneesh</firtName>

    <lastName>T.G</lastName>

    <age>25</age>

</person>